a) Ta có: \(7\cdot\dfrac{3}{14}-\dfrac{1}{14}\)
\(=\dfrac{3}{2}-\dfrac{1}{14}\)
\(=\dfrac{21}{14}-\dfrac{1}{14}\)
\(=\dfrac{10}{7}\)
b) Ta có: \(\dfrac{3}{2}+\dfrac{7}{4}:\dfrac{5}{2}\)
\(=\dfrac{3}{2}+\dfrac{7}{4}\cdot\dfrac{2}{5}\)
\(=\dfrac{3}{2}+\dfrac{7}{10}\)
\(=\dfrac{15}{10}+\dfrac{7}{10}=\dfrac{22}{10}=\dfrac{11}{5}\)
Lời giải:
\(7\times \frac{3}{14}-\frac{1}{14}=\frac{7\times 3}{14}-\frac{1}{14}=\frac{21}{14}-\frac{1}{14}=\frac{21-1}{14}=\frac{20}{14}=\frac{2\times 10}{2\times 7}=\frac{10}{7}\)
\(\frac{3}{2}+\frac{7}{4}:\frac{5}{2}=\frac{3}{2}+\frac{7}{4}\times \frac{2}{5}=\frac{3}{2}+\frac{7\times 2}{4\times 5}=\frac{3}{2}+\frac{7\times 2}{2\times 2\times 5}\)
\(=\frac{3}{2}+\frac{7}{2\times 5}=\frac{3\times 5}{2\times 5}+\frac{7}{2\times 5}=\frac{3\times 5+7}{2\times 5}=\frac{22}{2\times 5}=\frac{2\times 11}{2\times 5}=\frac{11}{5}\)
a. 7 x \(\dfrac{3}{14}\) - \(\dfrac{1}{14}\)
= \(\dfrac{7}{1}\) x \(\dfrac{3}{14}\) - \(\dfrac{1}{14}\)
= \(\dfrac{98}{14}\) x \(\dfrac{3}{14}\) - \(\dfrac{1}{14}\)
= \(\dfrac{3}{2}\) - \(\dfrac{1}{14}\)
= \(\dfrac{21}{14}\) - \(\dfrac{1}{14}\)
= \(\dfrac{10}{7}\)
b. \(\dfrac{3}{2}\) + \(\dfrac{7}{4}\) : \(\dfrac{5}{2}\)
= \(\dfrac{6}{4}\) + \(\dfrac{7}{4}\) : \(\dfrac{5}{2}\)
= \(\dfrac{13}{4}\) : \(\dfrac{5}{2}\)
= \(\dfrac{13}{4}\) . \(\dfrac{2}{5}\)
= \(\dfrac{13}{10}\)
a ) 7 x \(\dfrac{3}{14}\) - \(\dfrac{1}{14}\) = \(\dfrac{7}{1}\) x \(\dfrac{3}{14}\) - \(\dfrac{1}{14}\) = \(\dfrac{7x3}{1x14}\) - \(\dfrac{1}{14}\) = \(\dfrac{21}{14}\) - \(\dfrac{1}{14}\) = \(\dfrac{20}{14}\) = \(\dfrac{10}{7}\)
Mình chỉ làm đến đây thôi , mình có việc phải đi rồi 
Bye
a) Ta có: =32−114=32−114
=107=107
b) Ta có: =32+74⋅25=32+74⋅25
=1510+710=2210=115
