Question

(6x^3-4x^2+3x):(-1/2x)

 

Answer 1

`@` `\text {Ans}`

`\downarrow`

`(6x^3-4x^2+3x) \div (-1/2x)`

`= 6x^3 \div (-1/2x) - 4x^2 \div (-1/2x) + 3x \div (-1/2x)`

`= -12x^2 + 8x - 6`

Answer 2

\(=-6x^3:\dfrac{1}{2}x+4x^2:\dfrac{1}{2}x-3x:\dfrac{1}{2}x\)

=-12x^2+8x-6