=>5x^2+10x-5x^2+20=0
=>10x=-20
=>x=-2
`5x(x+2) -5x^2 +20 =0`
`<=> 5x^2+10x-5x^2+20=0`
`<=> 10x +20 =0`
`<=> 10x =-20`
`<=> x = -20/10 =-2`
Vậy `S={-2}`
=>5x^2+10x-5x^2+20=0
=>10x=-20
=>x=-2
`5x(x+2) -5x^2 +20 =0`
`<=> 5x^2+10x-5x^2+20=0`
`<=> 10x +20 =0`
`<=> 10x =-20`
`<=> x = -20/10 =-2`
Vậy `S={-2}`
Tìm x biết :
a) 2(x + 5) - x^2 - 5x = 0
b) x^3 - 5x^2- 4x + 20 = 0
c) (2x - 1)^2 - (x + 3)^2
Tìm x biết :
a) 2(x + 5) - x^2 - 5x = 0
b) x^3 - 5x^2- 4x + 20 = 0
c) (2x - 1)^2 - (x + 3)^2 = 0
5x - 20 - (x-4)^2 = 0(tìm x)
Tìm x: \(-x^4+4x^2-5x^2+20=0\)
a) Tìm x biết : x^3 -4x^2+5x-20>0
b) Biết 3x2 -3xy-5x+5y =0 và x≠ 𝑦 Tính giá trị S = x2 -x
x mu 2 - x -20=0
x mu 2 +80x -20=0
x mu 2 +5x -6=0
Tìm x
5x(x-3)(-2x+6)=0
(X+2)2-(x-2)(x+2)=0
(2x+3)2-(x-1)=0
X3-8=(x-2)3
X3+5x2-4x-20=0
a) 2x²=x
b) x²-1/36=0
c) x²-14x+49=0
d) x³-3x²+3x-1=0
e) x(x-2) -5x+10=0
f) x³-5x²+4x-20=0
g) x³-x=0
bài 5 ; tìm x
f, a mũ 2 + x -x mũ 2 - a = a
g, x mũ 2 + 3x - ( 2x + 6 ) = 0
h, 5x + 20 - x mũ 2 - 4x =0
m, x mũ 3 - 5x mũ 2 - x + 5 = 0
n, x ( x - 3 ) - 7x + 21 = 0
x2-4x+5x-20=0