`5(x+1)+75=126`
`=> 5(x+1)=51`
`=> x+1=51/5`
`=> x= 46/5`
\(5\left(x+1\right)+75=126\)
\(5\left(x+1\right)=51\)
\(x+1=10,2\)
\(x=9,2\)
\(5.\left(x+1\right)=51\)
\(x+1=10,2\)
\(\Rightarrow x=9,2\)
`5.(x+1)+75=126`
`<=> 5(x+1) = 126 -75`
`5(x+1) = 51`
`x+1 = 51 : 5 = 10,2`
`x = 10,2 - 1 =9,2`
Vậy `x=9,2`
5.(x+1)+75=126 <=> 5x+5+75=126 <=> 5x= 126-5-75 <=> 5x= 46 <=> x=46/5
`5.(x+1)+75=126`
`5.(x+1)=126-75`
`5.(x+1)=51`
`x+1=51:5`
`x+1=51/5`
`x=51/5 - 1`
`x=51/5 - 5/5`
`x=46/5`
