Question

`4x^2−1−(1−2x)(−2x)=1`

Answer 1

\(4x^2-1-\left(1-2x\right)\left(-2x\right)=1\\ 4x^2-1+2x-4x^2-1=0\\ 2x-2=0\\ 2x=2\\ x=1\)

Answer 2

`4x^2−1−(1−2x)(−2x)=1`

`<=> 4x^2 - 1 + 2x - 4x^2 = 1`

`<=> 4x^2 - 4x^2 + 2x = 1 + 1`

`<=> 2x = 2`

`<=> x = 2:2`

`<=> x = 1`

Answer 3

\(4x^2-1-\left(1-2x\right)\left(-2x\right)=1\\ 4x^2-1-\left(4x^2-2x\right)=1\\ 4x^2-1-4x^2+2x=1\\ 2x=2\\ x=1\)

Answer 4

4x2−1−(1−2x)(−2x)=14x2−1−(4x2−2x)=14x2−1−4x2+2x=12x=2x=1