Question

4^x+1+4⁰= 65

Answer 1

\(4^{x+1}+4^0=65\)

\(4^{x+1}+1=65\)

\(4^{x+1}=65-1\)

\(4^{x+1}=64\)

\(4^{x+1}=4^3\)

=> X+1=3

      x    =2

Vậy x=2

Answer 2

\(4^{x+1}\) + \(4^0\) = 65

\(\Rightarrow\) \(4^{x+1}\) + 1 = 65

\(\Rightarrow\) \(4^{x+1}\) = 65 - 1 = 64 = \(4^3\)

\(\Rightarrow\) x + 1 = 3

\(\Rightarrow\) x = 3 - 1 = 2

Vậy x = 2 .

Answer 3

`4^{x+1}+4^0=65`

`=>4^{x+1}+1=65`

`=>4^{x+1}=65-1=64=4^3`

`=>x+1=3`

`=>x=2`

Vậy `x=2`

Answer 4

\(4^x\).\(4^1\)+1=65

\(4^x\).4=65-1

\(4^x\).4=64

\(4^x\)=64:4

\(4^x\)=16

\(4^x\)=\(4^2\)

\(\Rightarrow\)x=2

Answer 5

Ta có: \(4^{x+1}+4^0=65\)

\(\Leftrightarrow4^{x+1}+1=65\)

\(\Leftrightarrow4^{x+1}=64\)

\(\Leftrightarrow x+1=3\)

hay x=2

Vậy: x=2

Answer 6

x=2

Answer 7

4^x+1+4⁰=65

4^x+1      =65-1

4^x+1      =64

⇒4^x+1   =4³

⇒x+1=3

       x=3-1

       x=2

Answer 8

x=2

Answer 9

x=2