Question

(3x-1)²-(x+3)²=0

Answer 1

\(\left(3x-1\right)^2-\left(x+3\right)^2=0\)

\(\Leftrightarrow\left(3x-1-x-3\right)\left(3x-1+x+3\right)=0\)

\(\Leftrightarrow\left(2x-4\right)\left(4x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-\dfrac{1}{2}\end{matrix}\right.\)

Answer 2

(3x - 1 - x - 3)(3x - 1 + x + 3) = 0

(2x - 4)(4x + 2) = 0

2x - 4 = 0       hoặc            4x + 2 = 0

x = 2              hoặc             x = - 1/2

Answer 3

4(x-2)(2x+1)=0

x-2=0 hoặc 2x+1=0

x=2 hoặc x=-1/2

Answer 4

4(x-2)(2x+1)=0

x-2=0 hoặc 2x+1=0

x=2 hoặc x=-1/2