\(2x^2-10x+8\\ =2\left(x^2-5x+4\right)\\ =2\left(x^2-x-4x+4\right)\\ =2\left[\left(x^2-x\right)-\left(4x-4\right)\right]\\ =2\left[x\left(x-1\right)-4\left(x-1\right)\right]\\ =2\left(x-4\right)\left(x-1\right)\)
\(2x^2-10x+8\)
\(=2\left(x^2-5x+4\right)\)
\(=2\left(x^2-x-4x+4\right)\)
\(=2\left[x\left(x-1\right)-4\left(x-1\right)\right]\)
=2(x-1)(x-4)
`2x^2 - 10x + 8`
`= 2(x^2 - 5x + 4)`
`= 2(x^2 - 2.x.5/2 + 25/4 -2,25)`
`=2[(x - 5/2)^2 - (3/2)^2]`
`=2(x-5/2 - 3/2)(x-5/2 + 3/2)`
`=2(x-4)(x-1)`