2x-x0=35:33=32=9
=>2x-1=9
=>2x=9+1=10
=>x=10:2=5.
\(2x-x^0=3^5:3^3\\ 2x-1=3^{5-3}\\ 2x-1=3^2\\ 2x-1=9\\ 2x=9+1\\ 2x=10\\ x=\dfrac{10}{2}\\ x=5\)
Lời giải:
$2x-x^0=3^5:3^3$
$2x-1=3^2=9$
$2x=10$
$x=5$
2\(x\) - \(x^0\) = 35:33 ( đk \(x\ne\) 0)
2\(x\) - 1 = 32
2\(x\) = 9 + 1
2\(x\) = 10
\(x\) = 10: 2
\(x\) = 5
\(2x-x^0=3^5:3^3\)
⇒ \(2x-1=9\)
⇒ \(2x=10\)
⇒ \(x=5\).
Vậy x = 5
