Question

2.(x-2)=x²-4x+4
giải giúp mình gấp nha

 

Answer 1

=>(x-2)²=2(x-2)

=>(x-2)(x-4)=0

=>x=2 hoặc x=4

Answer 2

\(x-2=\left(x-2\right)^{^2}\)

\(\dfrac{1}{x-2}=1\)

\(x-2=1\)

\(x=3\)

Answer 3

`=> 2 . (x-2) = (x-2)^2 `

`=> (x-2)(x-2 -2) = 0`

`<=> (x-2)(x-4) = 0`

`<=>` \(\left[{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)

Answer 4

`2.(x-2) = x^2 - 4x +4 `

`<=> 2(x-2) = (x-2)^2`

`<=> 2(x-2) - (x-2)^2 =0`

`<=> (x-2)[2-x+2)] =0`

`<=>(x-2)(4-x)=0`

`<=>`\(\left[{}\begin{matrix}x-2=0\\4-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)

Vậy `S={2;4}`

Answer 5

\(2.\left(x-2\right)=x^2-4x+4\)

\(2\left(x-2\right)=\left(x-2\right)^2\)

\(\left(x-2\right)^2-2\left(x-2\right)=0\)

\(\left(x-2\right)\left(x-2-2\right)=0\)

\(\left(x-2\right)\left(x-4\right)=0\)

\(\Rightarrow x-2=0\) hoặc \(x-4=0\)

*) \(x-2=0\)

\(x=2\)

*) \(x-4=0\)

\(x=4\)

Vậy \(x=2\); \(x=4\)