Question

2/phân tích đa thức thành nhân tử
a/ 4x(x-1)-6x+6
3/tìm x
a/6x^2 -24x =0

Answer 1

2.
a) 4x(x-1)-6x+6
= 4x(x-1)-6(x-1)
= (4x-6)(x-1)
3.
a) 6x²-24x=0
    6x(x-4)=0
TH1: 6x=0         TH2: x-4=0
           x=0                     x=4
Vậy x\(\in\){0;4}

Answer 2

2. a. \(4x\left(x-1\right)-6x+6\)

\(=4x\left(x-1\right)-6\left(x-1\right)\)

\(=\left(4x-6\right)\left(x-1\right)\)

3. a. \(6x^2-24x=0\)

\(\Leftrightarrow6x\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}6x=0\\x-4=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)

Answer 3

Bài 3: 

a: \(\Leftrightarrow6x\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)