`2 cos^2 x-cos x-1=0`
`<=>` $\left[\begin{matrix} cos x=1\\ cos x=\dfrac{-1}{2}\end{matrix}\right.$
`<=>` $\left[\begin{matrix} x=k2\pi\\ x=\dfrac{+-2\pi}{3}+k2\pi\end{matrix}\right.$ `(k in ZZ)`
Vậy ptr có `3` họ nghiệm `x=k2pi` ; `x=[+-2\pi]/3+k2\pi` `(k in ZZ)`