\(=\left(\dfrac{2}{3}\right)^3\cdot\left(\dfrac{3}{2}\right)^3\cdot\dfrac{9}{4}=\dfrac{9}{4}\)
\(=\dfrac{8}{27}.\dfrac{243}{32}\\ =\dfrac{9}{4}\)
= \(\dfrac{8}{27}\). \(\dfrac{243}{32}\)
= \(\dfrac{9}{4}\)
\(=\left(\dfrac{2}{3}\right)^3\cdot\left(\dfrac{3}{2}\right)^3\cdot\dfrac{9}{4}=\dfrac{9}{4}\)
\(=\dfrac{8}{27}.\dfrac{243}{32}\\ =\dfrac{9}{4}\)
= \(\dfrac{8}{27}\). \(\dfrac{243}{32}\)
= \(\dfrac{9}{4}\)
5) (3-1/4+2/3) - (5-1/3-6/5) - (6-7/4+3/2) 6) (6-2/3+1/2) - (5+5/3-3/2)-(3-7/3+5/2)
7) (5/3-3/7+9)-(2+5/7-2/3)+(8/7-4/3-10) 8) (8-9/4+2/7)-(-6-3/7+5/4)-(3+2/4-9/7 pls help me
(3-1/4+2/3) - (5-1/3-6/5) - (6-7/4+3/2) (6-2/3+1/2) - (5+5/3-3/2)-(3-7/3+5/2)
(5/3-3/7+9)-(2+5/7-2/3)+(8/7-4/3-10) (8-9/4+2/7)-(-6-3/7+5/4)-(3+2/4-9/7 )
mọi người ơi giúp mik với ạ
3 - 2x - (5/4 - 7/5) = 9/20
x : (-2/3) mũ 3 = -2/3
(2/5) mũ 5 nhân x = (2/5) mũ 7
343/125 = (7/5) mũ x
(-1/3) nhân x = -1/243
Tính:
(-2 1/2) mũ 3
(1 + 1/2 - 1/4) mũ 2 nhân 2022
2 : (1/2 - 2/3) mũ 3
7 nhân 2 mũ 3 - 5 nhân {[10,51 + 4 nhân (3/4 - 2/5) mũ 2] - 2022}
1, ( -2/5 + 3/10 ) : ( 2/-5 + |-4/3 - 2| )
2, 12,5 . -5/7 + 9 3/4 - 1,5 . 5/7
3, -1/4 . -5/13 - 5/4 . -7/13 + 1/1,3
4, ( -3/4 + 5/13 ) : 2/7 - ( 2 1/4 + 8/13 ) : 2/7
5, ( 3 - 3/4 + 2/3 ) - ( 2 - 4/3 - 3/2 ) - ( 1 - 7/3 - 9/2 )
6, -1/3 - 8/35 + -2/9 - 1/135 z+ 4/5 + -4/9 + 3/7
(6 - 5/3 + 1/2) - (3 + 2/3 - 3/2) - (5 + 5/2 - 7/3)
Tính:
a) -5/7(14/5 - 7/10) : |-2/3| - 3/4(8/9 + 16/3) + 10/3(1/3 + 1/5)
b) 17/-26(1/6 - 5/3) : 17/13 - 20/3(2/5 - 1/4) + 2/3(6/5 - 9/2)
c) -8/9(9/8 - 3/2) + 5/4 : (5/2 - 15/4) - 3/4(10/9 - 8/3) : (-1/3)
d) 21/10 : (12/5 - 9/10) . (-4/7) - 3/2(1/6 - 7/12) + 1/5(3/2 - 1/4)
B=(3+1/3-2/3)-(2-2/3+5/2)-(5-5/2+4/3)
[16/3-2².5/3].[17/3-2².5/3].......[30/3-2².5/3]
A = ( 6 - 2 + 1 ) - ( 5 + 5 - 3 ) - ( 3 - 7 + 5)
3 2 3 2 3 2
A= 2^2 + 2^3 + 2^4 + 2^5 +...+ 2^100
B= 3^2 + 3^4 + 3^6 + ...+ 3^100
C=5^1 + 5^3 + 5^5 + ... + 5^99
Tính TỔNG QUÁT: S= a + a^2 + a^3 + a^4 + ...+ a^n