\(\dfrac{2}{3}+\dfrac{4}{3}=\dfrac{2+4}{3}=\dfrac{7}{3}\)
\(\dfrac{2}{3}+\dfrac{4}{3}=\dfrac{6}{3}=\dfrac{2}{1}=2\)
\(\dfrac{2}{3}+\dfrac{4}{3}=\dfrac{2+\text{4 }}{3}=\dfrac{6}{3}=2\)
\(\dfrac{2}{3}+\dfrac{4}{3}=\dfrac{2+4}{3}=\dfrac{6}{3}=2.\)
\(\dfrac{2}{3}+\dfrac{4}{3}=\dfrac{2+4}{3}=\dfrac{7}{3}\)
\(\dfrac{2}{3}+\dfrac{4}{3}=\dfrac{6}{3}=\dfrac{2}{1}=2\)
\(\dfrac{2}{3}+\dfrac{4}{3}=\dfrac{2+\text{4 }}{3}=\dfrac{6}{3}=2\)
\(\dfrac{2}{3}+\dfrac{4}{3}=\dfrac{2+4}{3}=\dfrac{6}{3}=2.\)
A 3/4; 2/3; 4/3
B 4/3; 3/4; 2/3
C 2/3; 3/4; 4/3
4/3; 2/3; 3/4
(2/3 + 3/4 + 4/5 + .........+ 2016 /2017 ) x ( 1/2 + 2/3 + 3/4 + ......+ 2015 /2016) - ( 1/2 + 2/3 + 3/4 + ........2016 /2017 ) x 2/3 + 3/4 + 4/5 + .....+ 2015/2016)
Tính: (2/3 + 3/4 + 4/5 + ... + 2016/2017) x (1/2 + 2/3 + 3/4 + ... + 2015/2016) – (1/2 + 2/3 + 3/4 + ... + 2016/2017) x (2/3 + 3/4 + 4/5 + ... + 2015/2016).
Các phân số 3/4 ; 7/7 ; 3/2 ; 4/3 được xếp theo thứ tự tăng dần là: (ghi cách giải)
A.3/4 ; 7/7 ; 3/2 ; 4/3
B.7/7 ; 4/3 ; 3/4 ; 3/2
C.3/2 ; 4/3 ; 7/7 ; 3/4
D.3/4 ; 7/7 ; 4/3 ; 3/2
(2/3 + 3/4 + 4/5 +... + 2016/2017) x (1/2 + 2/3 + 3/4 + ...+ 2015/2016) - (1/2 + 2/3 + 3/4 +...+2015/2016) x (2/3 + 3/4 + 4/5 +...+2015/2016)
(2/3 +3/4 +4/5+...+ 2016/2017) x ( 1/2+ 2/3+ 3/4+... + 2015/2016) - ( 1/2 + 2/3+ 3/4+ .... +2016/2017) x ( 2/3+ 3/4+ 4/5+... + 2015/2016) = ?
Giải chi tiết giúp mình nhé,
bài 1:
1/4 + 2/3 2/7 + 2/3 2/5 + 1/3 2/3 + 1/2 1/3 + 3/5 4/5 + 1/3
1/8 + 3/4 1/36 + 5/12 1/3 + 1/6 + 1/18.
bài 2:
15/16 - 3/16 17/18 - 5/6 3/4 - 4/9 1/2 - 2/5 5/6 - 3/10 3-1/3
4/5 - 1/10 5/2 - 1 5/8 - 2/5.
Tính: (2/3 + 3/4 + 4/5 + ... + 2016/2017) x (1/2 + 2/3 + 3/4 + ... + 2015/2016) – (1/2 + 2/3 + 3/4 + ... + 2016/2017) x (2/3 + 3/4 + 4/5 + ... + 2015/2016).
Thông cảm, mình không viết được phân số.
đề này hơi dài và hơi khó :
(2/3 + 3/4 + 4/5 + ... + 2016/2017) x (1/2 + 2/3 + 3/4 + ... + 2015/2016) - (1/2 + 2/3 + 3/4 +...+ 2016/2017) x (2/3 + 3/4 +4/5 + ... + 2015/2016) = ???
mong mn giải hộ -(ToT)- huhuhuhu
2+2+2+2+2+2+2+2+3+3+3+3+3+3+3+3+4+4x4+4+4
trả lời ......
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