Question

2 (x³-1) -2x² (x+2x⁴) + (4x⁵+4)x = 6

giúp mik vs ạ <3 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

_arigato:33

Answer 1

\(2\left(x^3-1\right)-2x^2\left(2x^4+x\right)+x\left(4x^5+4\right)\)

\(=2x^3-2-4x^6-2x^3+4x^6+4x\)

\(=4x-2\)

=22

Answer 2

2(x³ - 1) - 2x²(x + 2x⁴) + (4x⁵ + 4)x = 6

<=> 2x³ - 2 - 2x³ - 4x⁶ + 4x⁶ + 4x = 6

<=> 2x³ - 2x³ - 4x⁶ + 4x⁶ + 4x = 6 + 2

<=> 4x = 8

<=> x = 2

Answer 3

2x³-2-2x³-4x⁶+4x⁶+4x=6

-2+4x=6

4x=8 

x=2

Vậy x=2