\(\dfrac{1}{\dfrac{x+1}{x+10}}=\dfrac{1}{12}\left(đk:x\ne1;x\ne10\right)\)
`<=> (x+10)/(x+1) =1/12 `
`<=> 12x +120 = x+1`
`<=> 12x -x = 1-120`
`<=> 11x = -119`
`<=> x=-119/11`
Vậy `S={-119/11}`
\(\Leftrightarrow\dfrac{x+10+x}{x\left(x+10\right)}=\dfrac{1}{12}\)
=>(2x+10)/(x^2+10x)=1/12
=>x^2+10x=12(2x+10)
=>x^2+10x=24x+120
=>x^2-14x-120=0
=>(x-20)(x+6)=0
=>x=20 hoặc x=-6