\(\dfrac{177}{x}-\dfrac{96}{x}+\dfrac{21}{x}=6\left(x\ne0\right)\\ \dfrac{177-96+21}{x}=6\\ \dfrac{102}{x}=6\\ 6\times x=102\\ x=102:6=17\)
\(\dfrac{177}{x}-\dfrac{96}{x}+\dfrac{21}{x}=6\)
\(\dfrac{1}{x}\left(177-96+21\right)=6\)
\(102:x=6\)
\(x=102:6\)
\(x=17\)
\(\dfrac{177}{x}\) - \(\dfrac{96}{x}\) + \(\dfrac{21}{x}\) = 6
\(\dfrac{1}{x}\) \(\times\)( 177 - 96 + 21) = 6
\(\dfrac{1}{x}\) \(\times\) (81 + 21) = 6
\(\dfrac{1}{x}\) \(\times\) 102 = 6
\(\dfrac{102}{x}\) = 6
\(x\) = 102 : 6
\(x\) = 17
