Câu hỏi của ha nguyen

Question

|1/2x-1/5|=|4/3-1/3x|

Nguyễn Ngọc Huy Toàn · Accepted Answer

$\left|\dfrac{1}{2}x-\dfrac{1}{5}\right|=\left|\dfrac{4}{3}-\dfrac{1}{3}x\right|$$\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{4}{3}-\dfrac{1}{3}x\\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{1}{3}x-\dfrac{4}{3}\end{matrix}\right.$$\Leftrightarrow\left[{}\begin{matrix}\dfrac{5}{6}x=\dfrac{23}{15}\\dfrac{1}{6}x=-\dfrac{17}{15}\end{matrix}\right.$$\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{46}{25}\x=-\dfrac{34}{5}\end{matrix}\right.$Câu trả lời: $\left|\dfrac{1}{2}x-\dfrac{1}{5}\right|=\left|\dfrac{4}{3}-\dfrac{1}{3}x\right|$$\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{4}{3}-\dfrac{1}{3}x\\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{1}{3}x-\dfrac{4}{3}\end{matrix}\right.$$\Leftrightarrow\left[{}\begin{matrix}\dfrac{5}{6}x=\dfrac{23}{15}\\dfrac{1}{6}x=-\dfrac{17}{15}\end{matrix}\right.$$\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{46}{25}\x=-\dfrac{34}{5}\end{matrix}\right.$

Bảo Linh · Answer

` |1/2x-1/5|=|4/3-1/3x|`$\Rightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{4}{3}-\dfrac{1}{3}x\\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{1}{3}x-\dfrac{4}{3}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}\left(\dfrac{1}{2}+\dfrac{1}{3}\right).x=\left(\dfrac{4}{3}+\dfrac{1}{5}\right)\\left(\dfrac{1}{2}-\dfrac{1}{3}\right).x=\left(\dfrac{1}{5}-\dfrac{4}{3}\right)\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}\dfrac{5}{6}.x=\dfrac{23}{15}\\dfrac{1}{6}.x=-\dfrac{17}{15}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{23}{15}:\dfrac{5}{6}\x=-\dfrac{17}{15}:\dfrac{1}{6}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{23}{15}\times\dfrac{6}{5}\x=-\dfrac{17}{15}\times6\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{46}{25}\x=-\dfrac{34}{5}\end{matrix}\right.$Vậy......`#BaoL i n h` Câu trả lời: ` |1/2x-1/5|=|4/3-1/3x|`$\Rightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{4}{3}-\dfrac{1}{3}x\\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{1}{3}x-\dfrac{4}{3}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}\left(\dfrac{1}{2}+\dfrac{1}{3}\right).x=\left(\dfrac{4}{3}+\dfrac{1}{5}\right)\\left(\dfrac{1}{2}-\dfrac{1}{3}\right).x=\left(\dfrac{1}{5}-\dfrac{4}{3}\right)\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}\dfrac{5}{6}.x=\dfrac{23}{15}\\dfrac{1}{6}.x=-\dfrac{17}{15}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{23}{15}:\dfrac{5}{6}\x=-\dfrac{17}{15}:\dfrac{1}{6}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{23}{15}\times\dfrac{6}{5}\x=-\dfrac{17}{15}\times6\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{46}{25}\x=-\dfrac{34}{5}\end{matrix}\right.$Vậy......`#BaoL i n h`

Chuu · Answer

` |1/2x-1/5|=|4/3-1/3x|`$\Rightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{4}{3}-\dfrac{1}{3}x\\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{1}{3}x-\dfrac{4}{3}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}\left(\dfrac{1}{2}+\dfrac{1}{3}\right).x=\left(\dfrac{4}{3}+\dfrac{1}{5}\right)\\left(\dfrac{1}{2}-\dfrac{1}{3}\right).x=\left(\dfrac{1}{5}-\dfrac{4}{3}\right)\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}\dfrac{5}{6}.x=\dfrac{23}{15}\\dfrac{1}{6}.x=-\dfrac{17}{15}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{23}{15}:\dfrac{5}{6}\x=-\dfrac{17}{15}:\dfrac{1}{6}\end{matrix}\right.$ $\Rightarrow\left[{}\begin{matrix}x=\dfrac{46}{25}\x=-\dfrac{34}{5}\end{matrix}\right.$ `#LeMichael`Câu trả lời: ` |1/2x-1/5|=|4/3-1/3x|`$\Rightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{4}{3}-\dfrac{1}{3}x\\dfrac{1}{2}x-\dfrac{1}{5}=\dfrac{1}{3}x-\dfrac{4}{3}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}\left(\dfrac{1}{2}+\dfrac{1}{3}\right).x=\left(\dfrac{4}{3}+\dfrac{1}{5}\right)\\left(\dfrac{1}{2}-\dfrac{1}{3}\right).x=\left(\dfrac{1}{5}-\dfrac{4}{3}\right)\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}\dfrac{5}{6}.x=\dfrac{23}{15}\\dfrac{1}{6}.x=-\dfrac{17}{15}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{23}{15}:\dfrac{5}{6}\x=-\dfrac{17}{15}:\dfrac{1}{6}\end{matrix}\right.$ $\Rightarrow\left[{}\begin{matrix}x=\dfrac{46}{25}\x=-\dfrac{34}{5}\end{matrix}\right.$ `#LeMichael`

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