`(1/2)^(x + 1) - 1/2 = -3/8`
`=> (1/2)^(x + 1)= -3/8 + 1/2`
`=> (1/2)^(x + 1) = -3/8 + 4/8`
`=> (1/2)^(x + 1) = 1/8`
`=> (1/2)^(x + 1) = (1/2)^3`
`=> x + 1 = 3`
`=>x=3-1`
`=>x=2`
Vậy: `x=2`
`(1/2)^(x+1) - 1/2 = -3/8`
`=> (1/2)^(x+1) = 1/2 -3/8`
`=> (1/2)^(x+1) = 1/8`
=`> (1/2)^(x+1) = (1/2)^3`
`=> x + 1 = 3`
`=> x =2`
Vậy ...
`(1/2)^(x+1) - 1/2 = -3/8`
`=> (1/2)^(x+1) = 1/2 -3/8`
`=> (1/2)^(x+1) = 1/8`
=`> (1/2)^(x+1) = (1/2)^3`
`=> x + 1 = 3`
`=> x =2`
Vậy ...
\(\dfrac{1}{2}^{x+1}\) \(-\dfrac{1}{2}\)\(=\dfrac{-3}{8}\)
\(\dfrac{1}{2}^{x+1}=-\dfrac{3}{8}+\dfrac{1}{2}\)
\(\dfrac{1}{2}^{x+1}=\dfrac{1}{8}\)
\(\dfrac{1}{2}^{x+1}=\left(\dfrac{1}{2}\right)^3\)
\(\Rightarrow x+1=3\)
\(\Rightarrow x=3-1\)
\(\Rightarrow x=2\)
Vậy x = 2
#\(haiyuan\)