Question

\(1-\dfrac{1}{1+\dfrac{2}{1-\dfrac{3}{1-4}}}\)

Giải hộ mik bằng latex đc thì càng tốt nhé

Answer 1

\(=1-\dfrac{1}{1+\dfrac{2}{1+1}}=1-\dfrac{1}{1+1}=1-\dfrac{1}{2}=\dfrac{1}{2}\)

Answer 2

\(1-\dfrac{1}{1+\dfrac{2}{1-\dfrac{3}{1-4}}}\)
\(=1-\dfrac{1}{1+\dfrac{2}{1+\dfrac{3}{3}}}\)
\(=1-\dfrac{1}{1+\dfrac{2}{1+1}}\)
\(=1-\dfrac{1}{1+1}\)
\(=1-\dfrac{1}{2}\)
\(=\dfrac{1}{2}\)
#AvoidMe

Answer 3

1-\(\dfrac{1}{1+\dfrac{2}{1+1}}\)=1-\(\dfrac{1}{1+1}\)=1-\(\dfrac{1}{2}\)=\(\dfrac{1}{2}\)