Question

Answer 1

a: \(\dfrac{3x+6}{x+2}=\dfrac{3\left(x+2\right)}{x+2}=3\)

b: \(\dfrac{x^2+2x}{3x+6}=\dfrac{x\left(x+2\right)}{3\left(x+2\right)}=\dfrac{x}{3}\)

c: \(\dfrac{x-1}{x^2-1}=\dfrac{x-1}{\left(x-1\right)\left(x+1\right)}=\dfrac{1}{x+1}\)

d: \(\dfrac{x^2+3x-4}{x-1}\)

\(=\dfrac{x^2+4x-x-4}{x-1}\)

\(=\dfrac{x\left(x+4\right)-\left(x+4\right)}{x-1}=\dfrac{\left(x+4\right)\left(x-1\right)}{x-1}=x+4\)