3A: Xét ΔPQR có \(\widehat{P}+\widehat{PQR}+\widehat{PRQ}=180^0\)
=>\(2\left(\widehat{MQR}+\widehat{MRQ}\right)=180^0-100^0=80^0\)
=>\(\widehat{MQR}+\widehat{MRQ}=40^0\)
Xét ΔMQR có \(\widehat{MRQ}+\widehat{MQR}+\widehat{RMQ}=180^0\)
=>\(\widehat{RMQ}=180^0-40^0=140^0\)
3B:
Xét ΔXYZ có \(\widehat{XYZ}+\widehat{XZY}+\widehat{YXZ}=180^0\)
=>\(\widehat{XYZ}+\widehat{XZY}=180^0-40^0=140^0\)
=>\(\widehat{KYZ}+\widehat{KZY}=\dfrac{140^0}{2}=70^0\)
Xét ΔKYZ có \(\widehat{KYZ}+\widehat{KZY}+\widehat{ZKY}=180^0\)
=>\(\widehat{ZKY}=180^0-70^0=110^0\)
Đúng 3
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