Question

Answer 1

1.A

2.D

3. Theo đề bài ta được :

\(-4x^2+6x-2+4\left(x-1\right)^2=0\)

\(\Leftrightarrow-\left(x-1\right)\left(x-\dfrac{1}{2}\right)+4\left(x-1\right)^2=0\)

\(\Leftrightarrow\left(x-1\right)\left(4x-4-x+\dfrac{1}{2}\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(3x-\dfrac{7}{2}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\3x-\dfrac{7}{2}=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{7}{6}\end{matrix}\right.\)

Chọn C

4.A

Answer 2

1A

2D

3C

4A