\(a.1\dfrac{1}{5}+\dfrac{4}{5}:x=0,75\\ \dfrac{6}{5}+\dfrac{4}{5}:x=\dfrac{3}{4}\\ \dfrac{4}{5}:x=\dfrac{3}{4}-\dfrac{6}{5}\\ \dfrac{4}{5}:x=-\dfrac{9}{20}\\ x=\dfrac{4}{5}:\dfrac{-9}{20}\\ x=-\dfrac{16}{9}\\ b.\dfrac{1}{9}\cdot3^4\cdot3^x=3^7\\ \dfrac{1}{3^2}\cdot3^4\cdot3^x=3^7\\ 3^2\cdot3^x=3^7\\ 3^{x+2}=3^7\\ x+2=7\\ x=7-2=5\\ c.\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{16}\\ \left(x+\dfrac{1}{2}\right)^2=\left(\dfrac{1}{4}\right)^2\\ TH1:x+\dfrac{1}{2}=\dfrac{1}{4}\\ x=\dfrac{1}{4}-\dfrac{1}{2}=-\dfrac{1}{2}\\ TH2:x+\dfrac{1}{2}=-\dfrac{1}{4}\\ x=-\dfrac{1}{4}-\dfrac{1}{2}=-\dfrac{3}{4}\\ d.\dfrac{1}{2}x-\dfrac{2}{3}=\dfrac{5}{4}\\ \dfrac{1}{2}x=\dfrac{5}{4}+\dfrac{2}{3}=\dfrac{23}{12}\\ x=\dfrac{23}{12}:\dfrac{1}{2}\\ x=\dfrac{23}{6}\\ e.3-\dfrac{1}{2}x=1\\ \dfrac{1}{2}x=3-1\\ \dfrac{1}{2}x=2\\ x=2:\dfrac{1}{2}\\ x=4\\ g.\dfrac{1}{3}x+\sqrt{16}=5\\ \dfrac{1}{3}x+4=5\\ \dfrac{1}{3}x=5-4=1\\ x=1:\dfrac{1}{3}\\ x=3\)