\(a)A=1\dfrac{13}{15}\cdot\left(0,5\right)^2\cdot3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\\ =\dfrac{28}{5}\cdot\dfrac{1}{4}+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\\ =\dfrac{7}{5}+\left(\dfrac{32}{60}-\dfrac{79}{60}\right)\cdot\dfrac{24}{47}\\ =\dfrac{7}{5}+\dfrac{-47}{60}\cdot\dfrac{24}{47}\\ =\dfrac{7}{5}-\dfrac{24}{60}\\ =\dfrac{21}{15}-\dfrac{6}{15}\\ =\dfrac{15}{15}\\ =1\\ b)B=\left(\dfrac{151515}{161616}+\dfrac{17^9}{17^{10}}\right)-\left(\dfrac{1500}{1600}-\dfrac{176}{187}\right)\\ =\left(\dfrac{15\cdot10101}{16\cdot10101}+\dfrac{1}{17}\right)-\left(\dfrac{15}{16}-\dfrac{176}{187}\right)\\ =\dfrac{15}{16}+\dfrac{1}{17}-\dfrac{15}{16}+\dfrac{176}{187}\\ =\dfrac{1}{17}-\dfrac{176}{187}\\ =-\dfrac{15}{17}\)
c: \(C=2^4\cdot5-\left[131-\left(13-4\right)^2\right]\)
\(=16\cdot5-\left[131-9^2\right]\)
=80-(131-81)
=80-50=30
d: \(D=\left(-8\right)^2:\left\{25-18:\left[\left(5^2+2^2\right):11-2024^0\right]\right\}\)
\(=64:\left\{25-18:\left[\dfrac{\left(25+4\right)}{11}-1\right]\right\}\)
\(=64:\left\{25-18:\left(\dfrac{29}{11}-1\right)\right\}\)
\(=64:\left\{25-18:\dfrac{18}{11}\right\}=64:\left(25-11\right)=\dfrac{64}{14}=\dfrac{32}{7}\)
