a) MTC: \(3\left(x-4\right)\left(x+4\right)\)
+, \(\dfrac{-7}{x-4}=\dfrac{-21\left(x+4\right)}{3\left(x-4\right)\left(x+4\right)}\)
+, \(\dfrac{3}{3x+12}=\dfrac{3}{3\left(x+4\right)}=\dfrac{3\left(x-4\right)}{3\left(x-4\right)\left(x+4\right)}\)
+, \(\dfrac{-5}{16-x^2}=\dfrac{5}{x^2-16}=\dfrac{5}{\left(x-4\right)\left(x+4\right)}=\dfrac{15}{3\left(x-4\right)\left(x+4\right)}\)