Lời giải:
a.
\(A=\frac{x(x+2y)+x(x-2y)}{(x-2y)(x+2y)}+\frac{4xy}{x^2-4y^2}\\ =\frac{2x^2}{(x-2y)(x+2y)}+\frac{4xy}{(x-2y)(x+2y)}\\ =\frac{2x^2+4xy}{(x-2y)(x+2y)}\\ =\frac{2x(x+2y)}{(x-2y)(x+2y)}=\frac{2x}{x-2y}\)
b. Khi $x=1, y=3$ thì:
$A=\frac{2.1}{1-2.3}=\frac{2}{-5}$