AN+NC=AC
=>NC+6=13,5
=>NC=7,5cm
Xét ΔABC có \(\dfrac{AM}{MB}=\dfrac{AN}{NC}\left(\dfrac{4}{5}=\dfrac{6}{7,5}\right)\)
nên MN//BC
Xét ΔABC có MN//BC
nên \(\dfrac{MN}{BC}=\dfrac{AN}{AC}\)
=>\(\dfrac{MN}{12}=\dfrac{6}{13,5}=\dfrac{4}{9}\)
=>\(MN=\dfrac{12\cdot4}{9}=\dfrac{48}{9}=\dfrac{16}{3}\left(cm\right)\)