Question

Answer 1

h: \(x^2-6x=-9\)

=>\(x^2-6x+9=0\)

=>\(\left(x-3\right)^2=0\)

=>x-3=0

=>x=3

i: \(x^2-x-6=0\)

=>\(x^2-3x+2x-6=0\)

=>\(\left(x-3\right)\left(x+2\right)=0\)

=>\(\left[{}\begin{matrix}x-3=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)