\(5)(2x+1)^3\\=(2x)^3+3\cdot(2x)^2\cdot1+3\cdot2x\cdot1^2+1^3\\=8x^3+12x^2+6x+1\\---\\6)(3x+2)^3\\=(3x)^3+3\cdot(3x)^2\cdot2+3\cdot3x\cdot2^2+2^3\\=27x^3+54x^2+36x+8\\---\\\)
\(7)(2x-3)^3\\=(2x)^3-3\cdot(2x)^2\cdot3+3\cdot2x\cdot3^2-3^3\\=8x^3-36x^2+54x-27\\---\\8)(3x-1)^3\\=(3x)^3-3\cdot(3x)^2\cdot1+3\cdot3x\cdot1^2-1^3\\=27x^3-27x^2+9x-1\)
#\(Toru\)