Vẽ tia Bz // Ax // Cy
Do Bz // Ax
⇒ ∠zBA = ∠xAB = 60⁰ (so le trong)
Do Bz // Cy
⇒ ∠zBC = ∠yCB = 20⁰ (so le trong)
⇒ ∠ABC = ∠zBA + ∠zBC
= 60⁰ + 20⁰
= 80⁰
Kẻ thêm Bz//Cy//Ax
Ta có: Ax//Bz
\(\Rightarrow\widehat{xAB}=\widehat{zBA}\) (so le trong)
\(\Rightarrow\widehat{\text{z}BA}=60^o\)
Ta có: Bz//Cy
\(\Rightarrow\widehat{\text{y}CB}=\widehat{zBC}\)
\(\Rightarrow\widehat{zBC}=20^o\)
Mà: \(\widehat{zBA}+\widehat{zBC}=\widehat{ABC}\) (kề)
\(\Rightarrow\widehat{\text{A}BC}=60^o+20^o=80^o\)