Đặt \(\widehat{M}=a;\widehat{N}=b;\widehat{P}=c;\widehat{Q}=d\)
Theo đề, ta có: b=a+10; c=b+10; d=c+10
=>c=a+10+10=a+20; d=a+20+10=a+30
a+b+c+d=360
=>a+a+10+a+20+a+30=360
=>4a+60=360
=>a=75
=>b=85; c=95; d=105
=>\(\widehat{M}=75^0;\widehat{N}=85^0;\widehat{P}=95^0;\widehat{Q}=105^0\)