2:
a: \(=\dfrac{37}{5}-\dfrac{7}{10}+\dfrac{5}{2}-\dfrac{43}{10}\)
\(=7,4+2,5-5=9,9-5=4,9\)
b: \(=\dfrac{-37}{10}\left(\dfrac{3}{2}+\dfrac{17}{2}\right)=-\dfrac{37}{10}\cdot10=-37\)
c: \(=\dfrac{3}{4}+\dfrac{1}{4}\cdot\dfrac{-3}{1}=\dfrac{3}{4}-\dfrac{3}{4}=0\)