b) \(x-\dfrac{-2}{3}=\dfrac{\dfrac{5}{11}+0,2-0,375}{\dfrac{9}{16}-\dfrac{15}{22}+\dfrac{3}{2}\left(-0,2\right)}\)
\(\Rightarrow x+\dfrac{2}{3}=\dfrac{-0,375+0,2+\dfrac{5}{11}}{\dfrac{3}{2}\cdot\dfrac{3}{8}-\dfrac{3}{2}\cdot\dfrac{5}{11}-\dfrac{3}{2}\cdot0,2}\)
\(\Rightarrow x+\dfrac{2}{3}=\dfrac{-\dfrac{3}{8}+0,2+\dfrac{5}{11}}{\dfrac{3}{2}\cdot\left(\dfrac{3}{8}-\dfrac{5}{11}-0,2\right)}\)
\(\Rightarrow x+\dfrac{2}{3}=\dfrac{-\left(\dfrac{3}{8}-\dfrac{5}{11}-0,2\right)}{\dfrac{3}{2}\left(\dfrac{3}{8}-\dfrac{5}{11}-0,2\right)}\)
\(\Rightarrow x+\dfrac{2}{3}=\dfrac{-1}{\dfrac{3}{2}}\)
\(\Rightarrow x+\dfrac{2}{3}=\dfrac{-2}{3}\)
\(\Rightarrow x=\dfrac{-2}{3}-\dfrac{2}{3}\)
\(\Rightarrow x=-\dfrac{4}{3}\)
Vậy: \(x=-\dfrac{4}{3}\)
=>\(x+\dfrac{2}{3}=\dfrac{\dfrac{5}{11}+\dfrac{1}{5}-\dfrac{3}{8}}{\dfrac{9}{16}-\dfrac{15}{22}+\dfrac{3}{-10}}=\dfrac{\dfrac{5}{11}+\dfrac{1}{5}-\dfrac{3}{8}}{\dfrac{3}{2}\left(\dfrac{3}{8}-\dfrac{5}{11}-\dfrac{1}{5}\right)}=-1:\dfrac{3}{2}=-\dfrac{2}{3}\)
=>x=-4/3
