\(a)-\dfrac{1}{3}x^2y\cdot\dfrac{3}{2}xy^3\\ =-\dfrac{1}{2}x^3y^4\\ b)-5xy^4\cdot\left(-0,2x^2y^2\right)\\ =x^3y^6\\ c)\left(-2x^2y\right)\cdot\left(5x^3y^3\right)\\ =-10x^5y^4\\ d)\left(-1\dfrac{1}{2}x^2y^3\right)^2\\ =\left(-\dfrac{3}{2}x^2y^3\right)^2\\ =\dfrac{9}{4}x^4y^6\)
3.
\(a.\dfrac{-1}{3}x^2y.\dfrac{3}{2}xy^3\)
\(=\left(\dfrac{-1}{3}.\dfrac{3}{2}\right)\left(x^2.x\right)\left(y.y^3\right)\)
\(=\dfrac{-1}{2}.x^3.y^4\)
\(b.-5xy^4.\left(-0.2x^2y^2\right)\)
\(=-5xy^4.\left(-0.2\right)x^2y^2\)
\(=\left(-5.-0,2\right)\left(x.x^2\right)\left(y^4.y^2\right)\)
\(=1.x^3.y^6\)
\(c.\left(-2x^2y\right).\left(5x^3y^3\right)\)
\(=\left(-2\right)x^2y.5x^3.y^3\)
\(=\left(-2.5\right)\left(x^2.x^3\right)\left(y.y^3\right)\)
\(=-10.x^5.y^4\)
\(d.\left(-1\dfrac{1}{2}x^2y^3\right)^2\)
\(=\left(\dfrac{-3}{2}\right)^2.\left(x^2\right)^2.\left(y^3\right)^2\)
\(=\dfrac{9}{4}.x^4.y^5\)
