Question

Answer 1

a: \(B=\dfrac{\left(x+2\right)^2-\left(x-2\right)^2+16}{2\left(x-2\right)\left(x+2\right)}\)

\(=\dfrac{x^2+4x+4-x^2+4x-4+16}{2\left(x-2\right)\left(x+2\right)}\)

\(=\dfrac{8\left(x+2\right)}{2\left(x-2\right)\left(x+2\right)}=\dfrac{4}{\left(x-2\right)}\)

b: B=1/2

=>(x-2)=8

=>x=10

c: B nguyên

=>x-2 thuộc {1;-1;2;-2;4;-4}

=>x thuộc {3;1;4;0;6}