\(a,\dfrac{4^2.4^3}{2^{10}}=\dfrac{\left(2^2\right)^2.\left(2^2\right)^3}{2^{10}}=\dfrac{2^4.2^6}{2^{10}}=\dfrac{2^{10}}{2^{10}}=1\)
\(b,\dfrac{45^{10}.5^{20}}{75^{15}}=\dfrac{\left(5.3^2\right)^{10}.5^{20}}{\left(5^2.3\right)^{15}}=\dfrac{5^{10}.3^{20}.5^{20}}{5^{30}.3^{15}}=\dfrac{5^{30}.3^{20}}{5^{30}.3^{15}}=3^5=243\)
Lời giải:
a.\(=\frac{(2^2)^2.(2^2)^3}{2^{10}}=\frac{2^4.2^6}{2^{10}}=\frac{2^{4+6}}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
b. \(=\frac{15^{10}.3^{10}.5^{20}}{15^{20}.5^{15}}\) \(=\frac{3^{10}.5^5}{15^{10}}=\frac{3^{10}.5^5}{3^{10}.5^{10}}=\frac{1}{5^5}\)
