Question

Answer 1

Answer 2

a) Bậc: 4

Hệ số cao nhất: 2

Hệ số tự do: 1

b) A + B = x² + 5

B = x² + 5 - A

= x² + 5 - (2x⁴ - 4x³ + 3x² - 4x + 1)

= x² + 5 - 2x⁴ + 4x³ - 3x² + 4x - 1

= -2x⁴ + 4x³ + (x² - 3x²) + 4x + (5 - 1)

= -2x⁴ + 4x³ - 2x² + 4x + 4

c) A : (x² + 1)

= (2x⁴ - 4x³ + 3x² - 4x + 1) : (x² + 1)

= (2x⁴ + 2x² - 4x³ - 4x + x² + 1) : (x² + 1)

= [(2x⁴ + 2x²) - (4x³ + 4x) + (x² + 1)] : (x² + 1)

= [2x²(x² + 1) - 4x(x² + 1) + (x² + 1)] : (x² + 1)

= (x² + 1)(2x² - 4x + 1) : (x² + 1)

= 2x² - 4x + 1