1: Khi x=4 thì \(A=\dfrac{4-7}{4}=\dfrac{-3}{4}\)
2: \(=\dfrac{3x-6-x^2-2x+2x^2-3x+6}{\left(x-2\right)\left(x+2\right)}\)
\(=\dfrac{x^2-2x}{\left(x-2\right)\left(x+2\right)}=\dfrac{x}{x+2}\)
3: \(P=A\cdot B=\dfrac{x}{x+2}\cdot\dfrac{x-7}{x}=\dfrac{x-7}{x+2}\)
Để P=2 thì x-7=2x+4
=>-x=11
=>x=-11