Question

Answer 1

a)

\(A\left(x\right)=2x^3+x-3x^2-2x^3-1+3x^2\\ =\left(2x^3-2x^3\right)-\left(3x^2-3x^2\right)+x-1\\ =x-1\)

Bậc : 1

b) 

\(A\left(x\right)=x-1\)

Có `A(x)=0`

`=>x-1=0`

`=>x=1`

Answer 2

a: =2x^3-2x^3+3x^2-3x^2+x-1

=x-1

=>Bậc là 1

b: A(x)=0

=>x-1=0

=>x=1