a: \(=\dfrac{x-2x-4+x-2}{\left(x-2\right)\left(x+2\right)}:\dfrac{x^2-4+10-x^2}{x+2}\)
\(=\dfrac{-6}{\left(x-2\right)\left(x+2\right)}\cdot\dfrac{x+2}{6}=\dfrac{-1}{x-2}\)
b: Để A<0 thì x-2>0
=>x>2
c: Để A nguyên thì \(x-2\in\left\{1;-1\right\}\)
=>\(x\in\left\{3;1\right\}\)

