\(a,\dfrac{5x-2}{3}=\dfrac{5-3x}{2}\\ =>2\left(5x-2\right)=3\left(5-3x\right)\\ =>10x-4=15-9x\\ =>10x+9x=15+4\\ =>19x=19\\ =>x=1\)
\(c,2.\left(x+\dfrac{3}{5}\right)=5-\left(\dfrac{13}{5}+x\right)\\ =>2x+\dfrac{6}{5}=5-\dfrac{13}{5}-x\\ =>2x+x=5-\dfrac{13}{5}-\dfrac{6}{5}\\ =>3x=\dfrac{6}{5}\\ =>x=\dfrac{6}{5}:3\\ =>x=\dfrac{2}{5}\\ e,\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\\ =>5.\left(7x-1\right)+30.2x=6.\left(16-x\right)\\ =>35x-5+60x-96+6x=0\\ =>101x=101\\ =>x=1\)
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