\(9.\left(-\dfrac{1}{3}\right)^2+\dfrac{1}{6}.\sqrt{4}\)
\(=9.\dfrac{1}{9}+\dfrac{1}{6}.2\)
\(=1+\dfrac{1}{3}\)
\(=\dfrac{4}{3}\)
\(9.\left(-\dfrac{1}{3}\right)^2+\dfrac{1}{6}.\sqrt{4}=9.\dfrac{1}{9}+\dfrac{1}{6}.2\)
\(=1+\dfrac{1}{3}=\dfrac{3}{3}+\dfrac{1}{3}=\dfrac{4}{3}\)