Question

Answer 1

\(\left(\dfrac{2}{3}-x\right)-\dfrac{1}{3}=7x-\dfrac{1}{4}\)

\(\Leftrightarrow\dfrac{2}{3}-x-\dfrac{1}{3}=7x-\dfrac{1}{4}\)

\(\Leftrightarrow7x+x=\dfrac{2}{3}-\dfrac{1}{3}+\dfrac{1}{4}\)

\(\Leftrightarrow8x=\dfrac{7}{12}\)

\(\Leftrightarrow x=\dfrac{7}{12}:8\)

\(\Leftrightarrow x=\dfrac{7}{96}\)

Answer 2

Lời giải:
$(\frac{2}{3}-x)-\frac{1}{3}=7x-\frac{1}{4}$

$\frac{2}{3}-x-\frac{1}{3}=7x-\frac{1}{4}$

$\frac{1}{3}-x=7x-\frac{1}{4}$

$\frac{1}{3}+\frac{1}{4}=x+7x$

$\frac{7}{12}=8x$

$x=\frac{7}{12}:8=\frac{7}{96}$