a)\(x+\dfrac{2}{3}=\dfrac{5}{6}\)
\(x=\dfrac{5}{6}-\dfrac{4}{6}=\dfrac{1}{6}\)
b)\(\dfrac{2}{7}+x=\dfrac{5}{9}\)
\(x=\dfrac{35}{63}-\dfrac{18}{63}=\dfrac{17}{63}\)
c)\(\dfrac{1}{6}+x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}-\dfrac{2}{12}=\dfrac{1}{4}\)
\(a.x+\dfrac{2}{3}=\dfrac{5}{6}\)
\(x=\dfrac{5}{6}-\dfrac{2}{3}\)
\(x=\dfrac{1}{6}\)
vậy x=\(\dfrac{1}{6}\)
\(b.\dfrac{2}{7}+x=\dfrac{5}{9}\)
\(x=\dfrac{5}{9}-\dfrac{2}{7}\)
\(x=\dfrac{17}{63}\)
vậy \(x=\dfrac{17}{63}\)
\(c.\dfrac{1}{6}+x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}-\dfrac{1}{6}\)
\(x=\dfrac{1}{4}\)
vậy \(x=\dfrac{1}{4}\)
