\(C=\left|x+2\right|+\left|3-x\right|+5>=\left|x+2+3-x\right|+5=10\)
Dấu = xảy ra khi -2<=x<=3
`C=|x-3|+|x+2|+5`
`C=|3-x|+|x+2|+5`
Vì `|3-x|+|x+2| >= |3-x+x+2|=5`
`=>|3-x|+|x+2|+5 >= 10`
Hay `C >= 10`
Dấu "`=`" xảy ra `<=>(3-x)(x+2) >= 0`
`<=>(x-3)(x+2) <= 0<=>-2 <= x <= 3`