Question

Answer 1

\(a,\dfrac{4}{5}+\dfrac{1}{3}.\dfrac{3}{5}\\ =\dfrac{4}{5}+\dfrac{1}{5}\\ 1\\ b,\dfrac{19}{13}-\dfrac{3}{8}+\dfrac{7}{13}-\dfrac{5}{8}\\ =\left(\dfrac{19}{13}+\dfrac{7}{13}\right)-\left(\dfrac{3}{8}+\dfrac{5}{8}\right)\\ =2-1\\ =1\)

Answer 2

a)

\(\dfrac{4}{5}+\dfrac{1}{3}.\dfrac{3}{5}\)

\(=\dfrac{4}{5}+\dfrac{1}{5}\)

\(=\dfrac{4+1}{5}\)

\(=1\)

b)

\(\dfrac{19}{13}-\dfrac{3}{8}+\dfrac{7}{13}-\dfrac{5}{8}\)

\(=\left(\dfrac{19}{13}-\dfrac{7}{13}\right)-\left(\dfrac{3}{8}+\dfrac{5}{8}\right)\)

\(=\dfrac{12}{13}-1\)

\(=\dfrac{-1}{13}\)