`a)` Với `x \ne -1` và `x \ne 3/2` có:
`[3x-5]/[2x-3]=[(3x-5)(x+1)]/[(2x-3)(x+1)]=[3x^2+3x-5x-5]/[2x^2+2x-3x-3]`
`=[3x^2-2x-5]/[2x^2-x-3]`
`=>M=2x^2-x-3`
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`b)` Với `x \ne +-2` có:
`[2x^2+3x-2]/[x^2-4]=[(x+2)(2x-1)]/[(x-2)(x+2)]=[2x-1]/[x-2]`
`=[(2x-1)(x-2)]/[(x-2)^2]=[2x^2-4x-x+2]/[x^2-4x+4]`
`=[2x^2-5x+2]/[x^2-4x+4]`
`=>M=2x^2-5x+2`