\(=\dfrac{9x^2-3xy-3x^2-xy}{\left(3x+y\right)\left(3x-y\right)}-\dfrac{2x}{y^2-9x^2}\)
\(=\dfrac{6x^2-4xy+2x}{\left(3x+y\right)\left(3x-y\right)}\)
\(=\dfrac{3\left(3x^2-2xy+2\right)}{\left(3x+y\right)\left(3x-y\right)}\)
\(=\dfrac{3\left(3-2\cdot1\cdot2+2\right)}{\left(3\cdot1+2\right)\left(3\cdot1-2\right)}=\dfrac{3}{1\cdot5}=\dfrac{3}{5}\)


