Question

Answer 1

\(\left(\dfrac{1}{2}\right)^2-\left(3.x\right)^2=0\)

\(\left(3.x\right)^2=\left(\dfrac{1}{2}\right)^2-0\)

\(\left(3.x\right)^2=\left(\dfrac{1}{2}\right)^2\)

\(x=\dfrac{1}{2}\div3\)

\(x=\dfrac{1}{6}\)

Answer 2

(12)2−(3.x)2=0<=>14−(3.x)2=0<=>(3.x)2=14<=>(3.x)2=⎧⎪ ⎪ ⎪ ⎪ ⎪⎨⎪ ⎪ ⎪ ⎪ ⎪⎩(12)2(−12)2<=>⎧⎪ ⎪⎨⎪ ⎪⎩3.x=123.x=−12<=>x∈(16;−1

Answer 3

\(\left(\dfrac{1}{2}\right)^2-\left(3.x\right)^2=0< =>\dfrac{1}{4}-\left(3.x\right)^2=0< =>\left(3.x\right)^2=\dfrac{1}{4}< =>\left(3.x\right)^2=\left\{{}\begin{matrix}\left(\dfrac{1}{2}\right)^2\\\left(-\dfrac{1}{2}\right)^2\end{matrix}\right.< =>\left\{{}\begin{matrix}3.x=\dfrac{1}{2}\\3.x=-\dfrac{1}{2}\end{matrix}\right.< =>x\in\left(\dfrac{1}{6};-\dfrac{1}{6}\right)\)